In: Statistics and Probability
A food safety guideline is that the mercury in fish should be below 1 part per million (ppm). Listed below are the amounts of mercury (ppm) found in tuna sushi sampled at different stores in a major city. Construct a 99% confidence interval estimate of the mean amount of mercury in the population. Does it appear that there is too much mercury in tuna sushi?
Mercury (ppm)
0.53
0.69
0.11
0.93
1.24
0.53
0.89
solution:-
given that
from the values
mean = 0.7029 , standard deviation = 0.3621
n = 7
degree of freedom df = n-1 = 7 - 1 = 6
we look into t table with df and probability of (1-0.99) is 0.01
critical value t = 3.707
confidence interval formula
=> mean +/- t * standard deviation/sqrt(n)
=> 0.7029 +/- 3.707 * 0.3621/sqrt(7)
=> 0.196 < μ < 1.210
Does it appear that there is too much mercury in tuna sushi?
=> Yes, because it is possible that the mean is greater than 1 ppm .Also at least one of the sample values exceeds 1 ppm , so at least some of the fish have too much mercury