Question

In: Computer Science

#include <stdio.h> #include <ctype.h> int main(void) { int ch; unsigned long int charcount=0, wordcount=0, linecount=0; while((ch=getchar())!=EOF){...

#include <stdio.h>

#include <ctype.h>

int main(void) {

int ch;

unsigned long int charcount=0, wordcount=0, linecount=0;

while((ch=getchar())!=EOF){

if(ch==' ' || ch=='\n' || ch=='\t' || ch=='\0' || ch=='\r') {

wordcount++;

}

if(ch=='\n' || ch=='\0') {

linecount++;

}

charcount++;

}

printf("%lu %lu %lu\n", charcount, wordcount, linecount);

getchar();

return 0;

}

When my code reads a blank line, it increment my wordcount by one.

How can I fix this problem? Could you help me with this problem?

Expert Solution

Screenshot of the code used:

The Output obtained:

The Code Used:

#include <stdio.h>
#include <ctype.h>
int main(void) {
   int ch,prev; //I have introduced another variable this will store the character just before the current character.
   unsigned long int charcount=0, wordcount=0, linecount=0;
   while((ch=getchar())!=EOF){
       //Actually there was a bug on line 10, to fix that we have to introduce some extra checking, in this case
       //I have introduced another check inside the if condition for counting the words.
       //So, what it's basically doing is, it will check if the previous character, just before the current character
       //is not an ' ','\n','\t','\0' or '\r' this will make sure that the line is not blanck, and if this condition
       //is violated than the wordcounter would not be incremented.
       if(ch==' ' || ch=='\n' || ch=='\t' || ch=='\0' || ch=='\r') {

           if(prev!=' ' && prev!='\n' && prev!='\t' && prev!='\0' && prev!='\r'){
               wordcount++;
           }
       }
       if(ch=='\n' || ch=='\0') {
       linecount++;
       }
       charcount++;
       prev =ch; //storing the current character as previous, for the next iteration.
   }
   printf("%lu %lu %lu\n", charcount, wordcount, linecount);
   getchar();
   return 0;
}

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venereology answered 7 months ago

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