Question

In python

import numpy as np

Given the array b = np.arange(-6, 4) compute and print

1.) The array formed by \(bi^2 - 1\), where the \(bi\) are the elements of the array b.

2.) The array formed by multiplying b with the scalar 100.

3.)The array formed by 2.0 b i in reverse order. (Note: the base 2.0 must be a floating point number; for integer values a ValueError: Integers to negative integer powers are not allowed. is raised.)

4.) The array delta of length len(b)-1 that contains the differences between subsequence entries of \(bi^3\), namely \(\deltai = b{i+1}^3 - bi^3 \) with 0 ≤ i < N − 1 where N is the length of b. Print both delta.shape and delta.

Answer 1

import numpy as np

b = np.arange(-6, 4) # result : b = [-6 -5 -4 -3 -2 -1 0 1 2 3]

The array formed by \(bi^2 - 1\), where the \(bi\) are the elements of the array b.

result_array = []

for i in b:

result_array.append(i^2 - 1)

print(result_array)

The array formed by multiplying b with the scalar 100.

result_array = []

for i in b:

result_array.append(i*100)

print(result_array)

The array formed by 2.0 b i in reverse order.

def reverse(list):

return(element for element in reversed(list))

result_array = []

b = reverse(b)

for i in b:

result_array.append(b*2.0)

print(result_array)

The array delta of length len(b)-1 that contains the differences between subsequence entries of \(bi^3\), namely \(\deltai = b{i+1}^3 - bi^3 \) with 0 ≤ i < N − 1 where N is the length of b. Print both delta.shape and delta.

delta = []

result_array = []

for i in b:

result_array.append[i^3]

for i in range(len(b)-1):

delta.append(abs(result_array[i] - result_array[i+1]))

print(delta)