In a group of 227 taking an experimental pill, 52 developed nausea. In a group of...

In a group of 227 taking an experimental pill, 52 developed nausea. In a group of 45 taking a placebo, 5 developed nausea. Construct a 95% confidence interval estimate for the difference between the proportion of nausea for those taking the pill and those taking the placebo.

Expert Solution

The 95% Confidence Interval for Proportions

For Experimental Pill: = 52/ 227 = 0.2291, 1 - = 0.7709, n₁ = 227,

For the Placebo: = 5/ 45 = 0.1111, 1 - = 0.8889, n₂ = 45,

The Z critical (2 tail) for = 0.05, is 1.96

The Confidence Interval is given by (- ) ME, where

(- ) = 0.2291 – 0.1111 = 0.118

The Lower Limit = 0.118 - 0.1069 = 0.0111

The Upper Limit = 0.118 + 0.1069 = 0.2249

The 95% Confidence Interval is (0.0111 , 0.2249)

orchestra answered 2 years ago

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