Question

THE FOLLOWING QUESTION IS FOR C PROGRAMMING LANGUAGE

Printing the decimal equivalent of a binary number. Write a program that accepts an integer (5 digits or fewer) containing only 0s and 1s (i.e., binary) and prints out its decimal equivalent using the remainder and division operator to select the "binary" digits one at a time. Make sure your input is tested for multiple options: incorrect characters, too many, too few, etc.

I need help making this program. No loops, if else, or while statements are allowed. Thank you!

Answer 1

#include <stdio.h>
// return 0 if numberis invalid and 1 if number is valid
int isInputValid(int number)
{
int temp;
if (number < 0)
{
printf("Opps!!! Number is Negative\n");
return 0;
}
else if (number > 99999)
{
printf("Opps!!! Number contain more than 5 digit\n");
return 0;
}
// if number is greater than highest possible valid number
else if (number > 11111)
{
printf("Opps!!! Invalid Number\n");
return 0;
}
else
{
while (number != 0)
{
// take last digit
temp = number % 10;
number = number / 10;
// check if digit is valid or not
if (!(temp == 0 || temp == 1)) {
printf("Opps!!! Invalid Number\n");
return 0;
}
}
}
return 1;
}

int convertToDecimal(int number){
int powerFactor = 1, temp, output = 0;
while (number != 0)
{
temp = number % 10;
number = number / 10;
output = output + temp*powerFactor;
powerFactor = powerFactor * 2;
}
return output;
}

int main() {
int number;
printf("Enter your number: ");
scanf("%d",&number);

if (isInputValid(number))
{
printf("Final Number: %d\n", convertToDecimal(number));
}
return 0;
}