A 2.50 m -long, 550 g rope pulls a 14.0 kg block of ice across a...

A 2.50 m -long, 550 g rope pulls a 14.0 kg block of ice across a horizontal, frictionless surface. The block accelerates at 2.40 m/s2 . How much force pulls forward on (a) the ice, (b) the rope?

Part A

Express your answer with the appropriate units.

Part B

Express your answer with the appropriate units.

Solutions

Expert Solution

mass of the rope m_r = 550*10^-3 kg

mass of the ice m_i = 14 kg

acceleration of the block a = 2.40 m/sec

(i)

pulling force on ice F = m_i*a

= 14kg*2.40m/s

= 33.6 N

(ii)

pulling force on thread F- m_ia = m_ra

F = (m_i+m_r)a

= (14+0.55)2.40

= 34.92 N

genius_generous answered 1 year ago

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