In: Math
At what point does the normal to y=1−3x−x2y=1−3x−x2 at (1,−3)(1,−3) intersect the parabola a second time?
Hint: The normal line is perpendicular to the tangent line. If two lines are perpendicular their slopes are negative reciprocals -- i.e. if the slope of the first line is mm then the slope of the second line is −1/m
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