In: Statistics and Probability
MUTUALLY EXCLUSIVE EVENTS AND THE ADDITION RULE
Determine whether the following pair of events are mutually exclusive.
1) A card is drawn from a deck.
C={It is a King} D={It is a heart}.
2) Two dice are rolled.
G={The sum of dice is 8} H={One die shows a 6}
3) A family has three children.
K={First born is a boy} L={The family has children of both sexes}
Use the addition rule to find the following probabilities.
1) A die is rolled, and the events E and F are as follows:
E={An even number shows} F={A number greater than 3 shows}
Find P(E or F)
Solution:
Part i) Determine whether the following pair of events are mutually exclusive.
1) A card is drawn from a deck.
C={It is a King}
D={It is a heart}.
There are 4 king cards out of which one is heart.
thus we have:
Since this event is not empty, events C and D are not mutually exclusive.
2) Two dice are rolled.
G={The sum of dice is 8}
G = { (2,6) , (3,5) , ( 4.4) , ( 5,3), (6,2) }
H={One die shows a 6}
H = { (1,6) ,(2,6) ,(3,6) ,(4,6) ,(5,6) ,(6,6) , (6,1) ,(6,2) ,(6,3) ,(6,4) ,(6,5) }
Thus we have:
Since this event is not empty, events G and H are not mutually exclusive.
3) A family has three children.
Sample Space:
S = { BBB , BBG , BGB , GBB , GGB, GBG , BGG , GGG }
K={First born is a boy}
K= { BBB , BBG , BGB , BGG }
L={The family has children of both sexes}
L = {BBG , BGB , GBB , GGB, GBG , BGG }
Thus we have:
Since this event is not empty, events L and K are not mutually exclusive.
Part ii) Use the addition rule to find the following probabilities.
1) A die is rolled, and the events E and F are as follows:
E={An even number shows} F={A number greater than 3 shows}
Find P(E or F)=.........?
P(E or F)= P(E) + P(F) - P( E and F)
Sample Space = S = { 1,2,3,4,5,6}
E={An even number shows}
E = { 2,4,6}
P(E) = 3/6
F={A number greater than 3 shows}
F = {4,5,6}
P(F) = 3/6
and
E and F = { 4,6 }
P( E and F) = 2/6
Thus
P(E or F)= P(E) + P(F) - P( E and F)
P(E or F)= 3/6 + 3/6 - 2/6
P(E or F)= ( 3+3-2) / 6
P(E or F)= 4/6
P(E or F)=2/3
P(E or F)= 0.6667