Question

In: Statistics and Probability

MUTUALLY EXCLUSIVE EVENTS AND THE ADDITION RULE Determine whether the following pair of events are mutually...

MUTUALLY EXCLUSIVE EVENTS AND THE ADDITION RULE

Determine whether the following pair of events are mutually exclusive.

1) A card is drawn from a deck.  

C={It is a King} D={It is a heart}.

2) Two dice are rolled.

G={The sum of dice is 8} H={One die shows a 6}

3) A family has three children.

K={First born is a boy} L={The family has children of both sexes}

Use the addition rule to find the following probabilities.

1) A die is rolled, and the events E and F are as follows:

E={An even number shows}   F={A number greater than 3 shows}

Find P(E or F)

Solutions

Expert Solution

Solution:

Part i) Determine whether the following pair of events are mutually exclusive.

1) A card is drawn from a deck.  

C={It is a King}

D={It is a heart}.

There are 4 king cards out of which one is heart.

thus we have:

Since this event is not empty, events C and D are not mutually exclusive.

2) Two dice are rolled.

G={The sum of dice is 8}

G = { (2,6) , (3,5) , ( 4.4) , ( 5,3), (6,2) }

H={One die shows a 6}

H = { (1,6) ,(2,6) ,(3,6) ,(4,6) ,(5,6) ,(6,6) , (6,1) ,(6,2) ,(6,3) ,(6,4) ,(6,5) }

Thus we have:

Since this event is not empty,  events G and H are not mutually exclusive.

3) A family has three children.

Sample Space:

S = { BBB , BBG , BGB , GBB , GGB, GBG , BGG , GGG }

K={First born is a boy}

K= { BBB , BBG , BGB , BGG }

L={The family has children of both sexes}

L = {BBG , BGB , GBB , GGB, GBG , BGG }

Thus we have:

Since this event is not empty,  events L and K are not mutually exclusive.

Part ii) Use the addition rule to find the following probabilities.

1) A die is rolled, and the events E and F are as follows:

E={An even number shows}   F={A number greater than 3 shows}

Find P(E or F)=.........?

P(E or F)= P(E) + P(F) - P( E and F)

Sample Space = S = { 1,2,3,4,5,6}

E={An even number shows}

E = { 2,4,6}

P(E) = 3/6  

F={A number greater than 3 shows}

F = {4,5,6}

P(F) = 3/6  

and

E and F = { 4,6 }

P( E and F) = 2/6

Thus

P(E or F)= P(E) + P(F) - P( E and F)

P(E or F)= 3/6 + 3/6 - 2/6

P(E or F)= ( 3+3-2) / 6

P(E or F)= 4/6

P(E or F)=2/3

P(E or F)= 0.6667


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