Question

In: Statistics and Probability

Ten samples of 30 boxes of cereal are weighed, and the means of the samples are...

Ten samples of 30 boxes of cereal are weighed, and the means of the samples are found to vary from 365.3 to 370.7 grams. What is the probability that another sample of 30 boxes will have a mean of less than 365.3 grams?

Z=(xbar-u) / (s/sqrt(n)) = -0.989 and P(Z <-0.986) = 0.1621

Answer is .1621 .. but how did they get it

Solutions

Expert Solution

Please keep the z tables ready for this
given that

z = -0.989

we need to find

p(z<-0.989)

P ( Z<−0.989 )=1−P ( Z<0.989 )=1−0.8389=0.1611

The probability that Z<−0.989 is equal to the blue area under the curve.

orchestra answered 2 years ago
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