In: Statistics and Probability
The students in University of Glasgow have done public survey and 200 people involved to the survey. It is proved that, 110 out of 200 people wish to get their master degrees in Us Universities. Compute the probability of randomly selected 7 students at least 6 of them wish to apply to US universities for their master degrees (according to the public survey)?
It is proved that, 110 out of 200 people wish to get their master degrees in Us Universities.
So, p = 110/ 200 = 0.55
7 students are randomly selected. So, n = 7
Let , X be the number of students who wish to apply to US universities for their master degrees.
X follows Binomial distribution with n = 7 and p = 0.55
We have to find at probability that least 6 of 7 wish to apply to US universities for their master degrees
i.e P( x >= 6 )
P( x >= 6 ) = P( x = 6 ) + P( x = 7 )
Using Binomial distribution formula,
So,
Similarly ,
So,
P( x >= 6 ) = 0.087195 + 0.015224 = 0.102419
The probability of randomly selected 7 students at least 6 of them wish to apply to US universities for their master degrees is 0.102419