In: Math
A social scientist would like to analyze the relationship between educational attainment (in years of higher education) and annual salary (in $1,000s). He collects data on 20 individuals. A portion of the data is as follows:
Salary Education
40 4
73 1
99 7
57 1
83 8
76 4
109 6
49 0
31 4
32 4
91 2
40 4
65 6
71 2
166 5
61 0
88 1
59 4
132 9
25 0
a. Find the sample regression equation for the model: Salary = β0 + β1Education + ε. (Round answers to 2 decimal places.)
Salaryˆ=
+ Education
b. Interpret the coefficient for Education.
As Education increases by 1 unit, an individual’s annual salary is predicted to increase by $8,590.
As Education increases by 1 unit, an individual’s annual salary is predicted to decrease by $8,590.
As Education increases by 1 unit, an individual’s annual salary is predicted to decrease by $6,220.
As Education increases by 1 unit, an individual’s annual salary is predicted to increase by $6,220.
c. What is the predicted salary for an individual who completed 5 years of higher education? (Round coefficient estimates to at least 4 decimal places and final answer to the nearest whole number.)
Salaryˆ $
using excel data analysis tool for regression,steps are: write
data>menu>data>data analysis>regression>enter
required labels>ok> and following o/p is obtained
Regression Statistics | ||||||
Multiple R | 0.4741 | |||||
R Square | 0.2248 | |||||
Adjusted R Square | 0.1817 | |||||
Standard Error | 32.0961 | |||||
Observations | 20 | |||||
ANOVA | ||||||
df | SS | MS | F | Significance F | ||
Regression | 1 | 5375.7 | 5375.7 | 5.22 | 0.0347 | |
Residual | 18 | 18542.8 | 1030.2 | |||
Total | 19 | 23918.6 | ||||
Coefficients | Standard Error | t Stat | P-value | Lower 95% | Upper 95% | |
Intercept | 49.9460 | 12.1530 | 4.1098 | 0.0007 | 24.4135 | 75.4785 |
X | 6.2233 | 2.7243 | 2.2844 | 0.0347 | 0.4998 | 11.9469 |
salary^ = 49.95 + 6.22*education
b)
As Education increases by 1 unit, an individual’s annual salary is predicted to increase by $6,220.
c)
salary^ = 49.95 + 6.22*education
salary^ = 49.95 + 6.22*5 = 81.063
salary^ = $81063