In: Computer Science
Q.N. 1:-
An AM index between 0 and 1 indicates what?
a. the AM signal is very small and will not be detected by the receiver |
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b. distortion of the signal will prevent detection and demodulation |
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c. the received modulated signal will have minimal distortion |
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d. the AM index is not important |
Q.N. 2:-
Given the following AM modulated signal, determine the original message, m(t):
s(t) = 2.5[1+0.5 cos(2π25kHzt)] cos(2π88MHzt)
a. m(t) = 1.25cos(2π25kHz*t) |
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b. m(t) = 1.25cos(2π88MHz*t) |
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c. m(t) = 2.5cos(2π25kHz*t) |
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d. m(t) = 2.5cos(2π88MHz*t) |
Q.N. 3:-
Given the following AM modulated signal, determine the occupied frequency bandwidth(note: assume double-sideband large carrier (DSB-LC):
s(t) = 2.4[1+0.7 cos(2π33Hz*t)] cos(2π10GHz*t)
a. Frequency bandwidth = 33 Hz |
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b. Frequency bandwidth = 66 Hz |
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c. Frequency bandwidth = 10GHz |
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d. Frequency bandwidth = 20GHz |
Q.N. 4:-
Given the following message and carrier equations, determine the AM modulated signal equation: m(t)=4cos(2π4kHz*t), c(t)=4cos(2π3GHz*t)
a. s(t)=2[1 + 0.67cos(2π4000t)]cos(2π3GHz*t) |
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b. s(t)=2[1 + 0.67cos(2π3E9t)]cos(2π4kHz*t) |
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c. s(t)=4[1 + 1cos(2π4000t)]cos(2π3E9t) |
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d. s(t)=4[1 + 1.5cos(2π3GHz*t)]cos(2π4000t) |