1. A rechargeable battery with emf 1.52 V and internal resistance 0.75 Ω is connected positive...

1. A rechargeable battery with emf 1.52 V and internal resistance 0.75 Ω is connected positive to positive and negative to negative with a 3.00 V battery with internal resistance 1.4 Ω. Assume the emf of each battery remains constant.

(a) Find the current.

(b) How much energy will be stored in the rechargeable battery in 1.00 minute?

(c) Determine the efficiency of this charging arrangement.

(d) How could the efficiency be improved (and wasted energy be reduced)?

Expert Solution

Use loop rule to find the current through the circuit. The rechargeable battery absorbs power and the other battery provides power. The ratio of power absorbed to power given is the efficiency. Energy is lost in heating resistors. Hence, energy efficiency can be improved by reducing the value of resistance

genius_generous answered 1 hour ago

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