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A 3kg particle moves along the X axis according to X(t) = 6t+3t2+2t3, where X is...

A 3kg particle moves along the X axis according to X(t) = 6t+3t²+2t³, where X is in meters and t is in seconds. What net force is acting on it at t = 3 s?

Expert Solution

We have the position of the particle varies with the time according to the equation as,

On differentiating the postion with respect to time,we get the velocity at time t,

ie,

On differentiating the velocity with respect to the time,we get the instantaneous acceleration for time t,

So,The instantaneous acceleration of the particle at time t, is given by,

By Newtons 2nd law of motion,we have,

The net unbalanced force acting on the particle,

We have the mass of the particle is,

at time the acceleration of the particle,

So,The instantaneous acceleration at time is,

So,The net force on the body at is,

ie,

genius_generous answered 2 years ago

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