In: Statistics and Probability
The Vice-Chancellor of the University of the Sunshine Coast claimed that the average cost of rental accommodation in the area close to campus was $155 per week. The Student Guild, being sceptical about the validity of this claim, took a random sample of 35 quotes and found that the average rental was $149.25 per week. On the basis of advice given to them by a local real estate agent, it could be assumed that the standard deviation of rental prices in the area was $22.50 per week.
1. State the direction of the alternative hypothesis used to test the Vice-Chancellor's claim. Type the letters gt (greater than), ge (greater than or equal to), lt (less than), le (less than or equal to) or ne (not equal to) as appropriate in the box.
2. Use the tables in the text to determine the critical value used
to conduct the test, assuming a 5% level of significance. If there
are two critical values, state only the positive
value.
3. Calculate the test statistic, reporting your answer to two
decimal places.
4. Is the null hypothesis rejected for this test? Type yes or
no.
5. If it is shown later that the average rental price is $150 per
week, determine the nature of the decision made in the test. Type
cd (correct decision), 1 (a Type I error was made) or 2 (a Type II
error was made) as appropriate.
6. Regardless of your answer for 4, if the null hypothesis was rejected, could we conclude that the Vice-Chancellor's claim is valid? Type yes or no.
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Answers
1) ne
2) 1.96
3) 1.51
4) no
5) cd
6) no