Question

In: Physics

On average, a lightning flash on Earth transfers about 30 C is transferred across 1 GV....

On average, a lightning flash on Earth transfers about 30 C is transferred across 1 GV.

Suppose that, in a single lightning flash, 27.7 C of charge is transferred through a potential difference of 2.44 GV. If all this energy could be used to accelerate a car of mass 1,427 kg car from rest, what speed would the car reach, in m/s?

NOTE: 1000 m/s is 2237 miles per hour!

Solutions

Expert Solution

In order to find the amount of energy required to accelerate the car, we have to first find the amount of energy required for the 27.7C to travel through a potential difference of 2.44 GV = 2.44 * 109

Energy of the lightning strike, EL = 27,7 * (2.44*109) = 6.7588*1010 J

This is the amount of enegry that would be obtained from a lightning flash transfering 27.7C.

In order to accelerate the car, this energy must be equal to the kinetic energy of the car as it accelerates,

i.e. EL = Kinetic Energy of the car = 6.7588 * 1010

We know that Kinetic Energy(KE) = (1/2) * m * v2   --> (1)

--> 6.7588 * 1010 = (1/2) * 1427 kg * v2

--> v2 = (6.7588 * 1010 * 2)/1427 = 94.7274 * 106

--> v = = 9732.8 m/s or 21,772.27 miles/h

Thus a lightning strike transferig 27.7C through a potential of 2.44GV would have the energy to accelerate a car to speeds of approx. 9,733 m/s or 21,772 miles/h, if the energy could ever be harnessed!

genius_generous answered 2 hours ago
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