Question

You will need to write a library of functions that uses pointers. Your functions must follow the headers below.

int intDivide(int numerator, int denominator, int *quo_ptr, int *rem_ptr);

Create a function to do integer division that gives the division result and remainder via output parameters, quo_optr and rem_ptr.  

Additionally, the function must return an int representing the success/failure of the function. The function should return 0 if it succeeds and -1 if there is a divide by zero error. (Note that you should not actually do the division if there will be a divide by zero error. Simply return -1.)

Answer 1

(I have written the total code to show how the code is working. If you need only the intDivide() function neglect the main function which I have given)

(Here the results of division will be in int only because we are performing integer division. Normally when we divide 5/2 the result will be 2.5. But here the result will be 2. Because the datatype int will neglect the values after decimal part.)

Code Explanation:

In the function first check if denominator is not equal to 0. If yes then calculate numerator / denominator and assign to *quo_pte
Then calculate numerator % denominator and assign to *rem_pte then return 0
If the If condition fails then return -1.

intDivide() function code:

int intDivide(int numerator, int denominator, int *quo_ptr, int *rem_ptr)
{
    if(denominator!=0)
    {
        *quo_ptr = numerator / denominator;
        *rem_ptr = numerator % denominator;
        return(0);
    }
    else
    {
        return(-1);
    }
}

code Implementation with main function:

#include <stdio.h>
int intDivide(int numerator, int denominator, int *quo_ptr, int *rem_ptr);
int main()
{
    int numerator, denominator, quo_ptr, rem_ptr;
    printf("Enter numerator: ");
    scanf("%d",&numerator);
    printf("Enter denominator: ");
    scanf("%d",&denominator);
    int res = intDivide(numerator, denominator, &quo_ptr, &rem_ptr);
    if(res == 0)
    {
        printf("division result is: %d\n",quo_ptr);
        printf("remainder result is: %d",rem_ptr);
    }
    else
    {
        printf("division by zero error");
    }
        
    return 0;
}

int intDivide(int numerator, int denominator, int *quo_ptr, int *rem_ptr)
{
    if(denominator!=0)
    {
        *quo_ptr = numerator / denominator;
        *rem_ptr = numerator % denominator;
        return(0);
    }
    else
    {
        return(-1);
    }
}

Sample O/P1:

Enter numerator: 23                                                                                                             
Enter denominator: 5                                                                                                            
division result is: 4                                                                                                           
remainder result is: 3   

Sample O/P2:

Enter numerator: 8                                                                                                              
Enter denominator: 0                                                                                                            
division by zero error 

Code Screenshot:

Sample O/P1 screenshot:

Sample O/P2 screenshot:

(If you still have any doubts regarding this answer please comment I will definitely help)