Question

In: Physics

Louise (80 lbs) and Tina (100 lbs) are going to have a jumping contest. To determine...

Louise (80 lbs) and Tina (100 lbs) are going to have a jumping contest. To determine who has to do the dinner dishes. Answer the following questions about their contest.

1.During the propulsive phase of the jump if Louise exerts an average of 1.3 times her body weight for .4 seconds and Tina exerts an average of 1.1 times her body weight for 0.7 seconds what will their take-off velocities be?

2. Who jumps higher? Who is in the air longer? (Be sure to calculate each of their jump heights and each of their time in the air to determine

Expert Solution

First, I will convert their weight to Newtons

Louise-

Tina -

For the purpose of this problem,we will also need their weight in kilograms

Louise-

Tina-

Part 1

To calculate their velocity, we need to find out the impulse, ot the momentum they added.

Louise

Her velocity is

Tina

Her velocity is

Part B

The height of the jump can be determined by the formula

Lousie

Tina

The time in the air will be double the time they take to reach the top, at which point their velocity will be zero. Therefore, we consider a deceleration equal to and a final velocity of zero.

This time doubled will be the time in the air

Louise

Therefore, time in air is

Tina

Therefore, time in air is

genius_generous answered 2 years ago

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