In: Math
Frequency |
|
Rock |
85 |
Paper |
110 |
Scissors |
105 |
Total |
300 |
null Hypothesis:Ho All choices occur with equal probability.
Alternate Hypothesis:Ha: Not all choices occur with equal probability.
degree of freedom =categories-1= | 2 | ||||
for 0.05 level and 2 degree of freedom :rejection region = | 5.991 | ||||
applying chi square goodness of fit test: |
relative | observed | Expected | residual | Chi square | |
category | frequency(p) | Oi | Ei=total*p | R2i=(Oi-Ei)/√Ei | R2i=(Oi-Ei)2/Ei |
Rock | 0.333 | 85.000 | 100.0000 | -1.50 | 2.250 |
Paper | 0.333 | 110.000 | 100.0000 | 1.00 | 1.000 |
Scissors | 0.333 | 105.000 | 100.0000 | 0.50 | 0.250 |
total | 1.000 | 300 | 300 | 3.5000 |
test statistic X2 = | 3.5000 |
since test statistic does not falls in rejection region we fail to reject null hypothesis | ||||||
we do not have have sufficient evidence to conclude that semifinal opponent over-represents certain choices |