Question

In: Statistics and Probability

INDIAN STUDENTS DATA FILE (MINITAB) Variable N N* Mean SE Mean StDev Minimum Q1 Median Q3...

INDIAN STUDENTS DATA FILE (MINITAB)

Variable N N* Mean SE Mean StDev Minimum Q1 Median Q3 Maximum
GRE Score 500 0 316.47 0.505 11.3 290 308 317 325 340
TOEFL Score 500 0 107.19 0.272 6.08 92 103 107 112 120
CGPA 500 0 8.5764 0.027 0.6048 6.8 8.1225 8.56 9.04 9.92
  1. What is the probability of students between CGPA 8 and 9?
  2. What is the probability of students above GRE 325 score?
  3. What is the GRE score middle 50% students?
  4. What is the TOEFL score of top 10% students?
  5. What is the CGPA of top 10% students?

Solutions

Expert Solution

a) probability of students between CGPA 8 and 9 = 68%

( because the mean is 8.5764 with ths standard deviation 0.6048. And according to empirical rule 68% of the data lie between 0ne standard deviation of the mean )

b)probability of students above GRE 325 score = 25%

( Because the third quartile is 325 that means that 75% of the data is below 325 and 25% is above 325)

c)GRE score middle 50% students = Median = 317

d)TOEFL score of top 10% students

Mean =107.19

Standard deviation, = 6.08

For top 10% we need to find the 90th percentile

P( Z < z ) = 0.9

P( Z < 1.282) = 0.9

z = 1.282

= 1.282

= 1.282

X = 107.18 + 6.08 * 1.282

X= 114.97

Hence , TOEFL score of top 10% students is 114.97

e)

CGPA of top 10% students

Mean =8.5764

Standard deviation, = 0.6048

For top 10% we need to find the 90th percentile

P( Z < z ) = 0.9

P( Z < 1.282) = 0.9

z = 1.282

= 1.282

= 1.282

X = 8.5764 + 0.6048 * 1.282

X= 9.35

Hence CGPA of top 10% students is 9.35


Related Solutions

Consider the computer output below. Two-Sample T-Test and CI Sample N Mean StDev SE Mean 1...
Consider the computer output below. Two-Sample T-Test and CI Sample N Mean StDev SE Mean 1 15 54.87 2.13 0.55 2 20 58.54 5.28 1.2 Difference = μ1-μ2 Estimate for difference: –3.91 95% upper bound for difference: ? T-test of difference = 0 (vs <): T-value = -2.82 (a) Fill in the missing values. Use lower and upper bounds for the P-value. Suppose that the hypotheses are H0: μ1-μ2=0 versus H1: μ1-μ2<0. Enter your answer; P-value, lower bound <P< Enter...
Minitab printout One-Sample T: weight of cats Descriptive Statistics (weight is in pounds) N Mean StDev...
Minitab printout One-Sample T: weight of cats Descriptive Statistics (weight is in pounds) N Mean StDev SE Mean 95% CI for μ 33 9.300 1.707 0.297 (8.694, 9.905) μ: mean of weight of cats Test Null hypothesis H₀: μ = 8.5 Alternative hypothesis H₁: μ ≠ 8.5 T-Value P-Value 2.69 0.011 a. Looking at the confidence interval estimate, write a confidence statement for the mean weight for all cats. b. State your decision for the null hypothesis and show how...
Using Minitab, calculate the mean, standard deviation, variance, and median of the following four data sets....
Using Minitab, calculate the mean, standard deviation, variance, and median of the following four data sets. Comment on the results. A B C D 100 50 50 75 100 75 100 75 100 100 100 75 100 125 100 100 100 150 150 175
Compute Median, Q1, Q3, and IQR for the following data below Given: 10, 20, 12, 17,...
Compute Median, Q1, Q3, and IQR for the following data below Given: 10, 20, 12, 17, and 16 **Provide interpretation of your calculations**
calculate the mean, median, mode, and standard deviation based on the data provided. Response # Q3:...
calculate the mean, median, mode, and standard deviation based on the data provided. Response # Q3: How many times have you called the police in the last year? 1 0 2 0 3 0 4 2 5 4 6 9 7 0 8 2 9 5 10 4 11 3 12 0 13 0 14 0 15 1 16 8 17 15 18 7 19 2 20 2 21 4 22 3 23 0 24 0 25 1 26 0...
Gender Mean S.D. Min Q1 Median Q3 Max Female 23.76 47.47 0 2 5 21 256...
Gender Mean S.D. Min Q1 Median Q3 Max Female 23.76 47.47 0 2 5 21 256 Male 14.23 21.16 0 1 5 15 84 female sample size: 62 male sample size: 30 9. Let’s look a little closer at the original dataset (both genders, without Audrey/Katrina added) and actually perform a hypothesis test. At α = 0.05​, can you support the claim that female hurricanes are more deadly than male hurricanes? 9a. (4 pts) Write out the hypotheses statements below...
Gender Mean S.D. Min Q1 Median Q3 Max Female 23.76 47.47 0 2 5 21 256...
Gender Mean S.D. Min Q1 Median Q3 Max Female 23.76 47.47 0 2 5 21 256 Male 14.23 21.16 0 1 5 15 84 Male sample size: 30 Female sample size: 62 Use the following data a) Which measure, the mean or the median, do you think better represents a typical number of deaths from a hurricane? Why? b) Based upon the mean and median, do you think that the Female named hurricanes are more deadly? Why? Or why not?...
ADVERTISEMENT
ADVERTISEMENT
ADVERTISEMENT