Question

In: Computer Science

Compare C++ speed to Python speed. To compare Execution Time of: c++ vs. Py : //...

Compare C++ speed to Python speed.


To compare Execution Time of: c++ vs. Py :
// this is c++ code // covert this code to python and compare their execution time

#include<time.h>
#include <iostream>
using namespace std;
#include <chrono> //for time
using namespace std::chrono;

void doSomething() //to insert any execution code here to measure its running time
{ int x=6795; // cout << "Enter 4-digit integer x ?\n"; cin >> x;
for (int i = 1000; i < 2000000; i++) //a constant number of iterations
{
if (i % 2) x = i + int(sqrt(x)); else x = i + x * x; //do any computation here
}
}

void computeTime()
{ auto start = high_resolution_clock::now(); //starting time in milli-seconds
doSomething();
auto stop = high_resolution_clock::now(); //stopping time in milli-seconds
auto duration = duration_cast<microseconds>(stop - start); //duration time in milli-seconds
cout << "duration= " << duration.count() << endl;
}

void main()
{
int more = 1;
while (more) { computeTime(); cout << "more? <0,1> "; cin >> more; }
system("pause");
}

==================================================

// ( Python version. Be careful to put correct indentation for Python code below)

#---------- Now Python code to do the same as above code in C++
import math
import datetime

def measureSpeed():

t1 = datetime.datetime.now().microsecond

x = 6795 # cout << "Enter 4-digit integer x ?\n"; cin >> x;
#for (int i = 1000; i < 2000000; i++) //a constant number of iterations
for i in range(1000,2000000,1):
if (i % 2):
x = i + math.sqrt(x) #x = i + int(sqrt(x));
else:
x = i + x * x #do any computation here

t2 = datetime.datetime.now().microsecond

print(t2)
print(t1)
print(t2-t1)


def main():
more=1
while(more):
more = input("Please enter <0 or 1> to stop or continue:\n")
print(f'You entered {more}')
if(more):
measureSpeed()

main()

=====================================================

Solutions

Expert Solution

ANSWER:

  • I have provided the properly commented  and indented code so you can easily copy the code as well as check for correct indentation.
  • I have provided the output image of the code so you can easily cross-check for the correct output of the code.
  • Have a nice and healthy day!!

CODE

  • C++11 CODE
#include<time.h>
#include <iostream>
#include <cmath>
using namespace std;
#include <chrono> //for time
using namespace std::chrono;

void doSomething() //to insert any execution code here to measure its running time
{ 
        int x=6795; // cout << "Enter 4-digit integer x ?\n"; cin >> x;
        for (int i = 1000; i < 2000000; i++) //a constant number of iterations
        {
                if (i % 2) 
                        x = i + int(sqrt(x));
                else
                        x = i + x * x; //do any computation here
        }
}

void computeTime()
{ 
        auto start = high_resolution_clock::now(); //starting time in milli-seconds
        doSomething();
        auto stop = high_resolution_clock::now(); //stopping time in milli-seconds
        auto duration = duration_cast<microseconds>(stop - start); //duration time in milli-seconds
        cout << "duration= " << duration.count() <<" Microseconds" << endl;
}

int main()
{
        int more = 1;
        while (more)
        { 
                computeTime();
                cout << "more? <0,1> ";
                cin >> more;
        }
        system("pause");
}
  • PYTHON CODE
import math
import datetime

def measureSpeed():
    # starting time, using datetime.datetime.now()
    t1 = datetime.datetime.now()
    
    # required code
    x = 6795 # cout << "Enter 4-digit integer x ?\n"; cin >> x;for (int i = 1000; i < 2000000; i++) //a constant number of iterations
    for i in range(1000,2000000,1):
        if (i % 2):
            x = i + math.sqrt(x) #x = i + int(sqrt(x));
        else:
            x = i + x * x #do any computation here
    # end time        
    t2 = datetime.datetime.now()
    
    # calculating duration, in seconds using total_seconds method of timedelta
    duration = (t2-t1).total_seconds()
    # converting seconds to microseconds
    durationMS = duration * (10**6)
    
    # displaying results
    print("duration = {:d} Microseconds".format(int(durationMS)))

# main function
def main():
    more=1
    # while loop, till more is 1
    while(more):
        # calling function measureSpeed
        measureSpeed()
        # prompting user, and converting input to integer using int function
        more = int(input("Please enter <0 or 1> to stop or continue:\n"))

# calling main
main()

OUTPUT IMAGE

  • C++ OUTPUT

  • Python OUTPUT


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