Question

A clinic took temperature readings of 250 flu patients over a weekend and discovered the temperature distribution to be Gaussian, with a mean of 101.30 °F and a standard deviation of 0.8450 °F.

Use this normal error curve area table to calculate each value.

a) What is the fraction of patients expected to have a fever greater than 103.50 °F?

fraction above 103.50 °F: _____________

b) What is the fraction of patients expected to have a temperature between 100.46 °F and 102.06 °F?

fraction between 100.46 °F and 102.06 °F: _____________

Normal Error Curve

Ordinate and Area for a Normal Error Curve |z| y Area 0.0 0.3989 0.0000 0.1 0.3970 0.0398 0.2 0.3910 0.0793 0.3 0.3814 0.1179 0.4 0.3683 0.1554 0.5 0.3521 0.1915 0.6 0.3332 0.2258 0.7 0.3123 0.2580 0.8 0.2897 0.2881 0.9 0.2661 0.3159 1.0 0.2420 0.3413 1.1 0.2179 0.3643 1.2 0.1942 0.3849 1.3 0.1714 0.4032 1.4 0.1497 0.4192 1.5 0.1295 0.4332 1.6 0.1109 0.4452 1.7 0.0941 0.4554 1.8 0.0790 0.4641 1.9 0.0656 0.4713 2.0 0.0540 0.4773 2.1 0.0440 0.4821 2.2 0.0355 0.4861 2.3 0.0283 0.4893 2.4 0.0224 0.4918 2.5 0.0175 0.4938 2.6 0.0136 0.4953 2.7 0.0104 0.4965 2.8 0.0079 0.4974 2.9 0.0060 0.4981 3.0 0.0044 0.498650 3.1 0.0033 0.499032 3.2 0.0024 0.499313 3.3 0.0017 0.499517 3.4 0.0012 0.499663 3.5 0.0009 0.499767 3.6 0.0006 0.499841 3.7 0.0004 0.499904 3.8 0.0003 0.499928 3.9 0.0002 0.499952 4.0 0.0001 0.499968 ∞ 0 0.5 z = (x – μ)/σ The area refers to the area between z = 0 and z = the table value.

Answer 1

a).the fraction of patients expected to have a fever greater than 103.50⁰ C is:-

[ using standard normal table ]

b).the fraction of patients expected to have a temperature between 100.46 °F and 102.06 °F is:-

[ using standard normal table ]

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