Question

I only need the table (sample market share and difference) thanks!

Based on sales over a six-month period, the five top-selling compact cars are Chevy Cruze, Ford Focus, Hyundai Elantra, Honda Civic, and Toyota Corolla (Motor Trend, November 2, 2011). Based on total sales, the market shares for these five compact cars were Chevy Cruze 24%, Ford Focus 21%, Hyundai Elantra 20%, Honda Civic 18%, and Toyota Corolla 17%. A sample of 400 compact car sales in Chicago showed the following number of vehicles sold.

Chevy Cruze	108
Ford Focus	92
Hyundai Elantra	64
Honda Civic	84
Toyota Corolla	52

Use a goodness of fit test to determine if the sample data indicate that the market shares for the five compact cars in Chicago are different than the market shares reported by Motor Trend. Using a .05 level of significance. Use Table 12.4.

The p-value is - Select your answer -between .05 and .025between .025 and .01between .10 and .05Item 1 .

What is your conclusion?
- Select your answer -Conclude that the markets shares for the five compact cars in Chicago differ from the market shares reported by Motor Trend.Conclude that the markets shares for the five compact cars in Chicago same from the market shares reported by Motor Trend.Item 2

What market share differences, if any, exist in Chicago? Round your answers to two decimal places. Enter negative values as negative numbers.

Compact Car	Hypothesized Market Share	Sample Market Share	Difference
Chevy Cruze	.24
Ford Focus	.21
Hyundai Elantra	.20
Honda Civic	.18
Toyota Corolla	.17

Answer 1

Solution:-

State the hypotheses. The first step is to state the null hypothesis and an alternative hypothesis.

Null hypothesis: The market shares for the five compact cars in Chicago are same as market shares reported by Motor Trend.

Alternative hypothesis: At least one of the proportions in the null hypothesis is false.

Formulate an analysis plan. For this analysis, the significance level is 0.05. Using sample data, we will conduct a chi-square goodness of fit test of the null hypothesis.

Analyze sample data. Applying the chi-square goodness of fit test to sample data, we compute the degrees of freedom, the expected frequency counts, and the chi-square test statistic. Based on the chi-square statistic and the degrees of freedom, we determine the P-value.

DF = k - 1 = 5 - 1
D.F = 4
(E_i) = n * p_i


X² = 11.23

where DF is the degrees of freedom, k is the number of levels of the categorical variable, n is the number of observations in the sample, E_i is the expected frequency count for level i, O_i is the observed frequency count for level i, and X² is the chi-square test statistic.

The P-value is the probability that a chi-square statistic having 4 degrees of freedom is more extreme than 11.23.

We use the Chi-Square Distribution Calculator to find P(X² > 11.23) = 0.024

Interpret results. Since the P-value (0.024) is less than the significance level (0.05), we cannot accept the null hypothesis.

From the above test we have sufficient evidence that the market shares for the five compact cars in Chicago are different than market shares reported by Motor Trend.