At an outdoor market, a bunch of bananas is set into oscillatory motion with an amplitude...

At an outdoor market, a bunch of bananas is set into oscillatory motion with an amplitude of 20.0 cm on a spring with a spring constant of 16.0 N/m. It is observed that the maximum speed of the bunch of bananas is 44.0 cm/s. What is the weight of the bananas in newtons?

Solutions

Expert Solution

Let the weight of the bananas in newtons is W.

Let the mass of the bananas is m.

Let the period of the oscillation is T.

Given that the amplitude A=20.0 cm=0.20 m.

The spring constant k=16.0 N/m.

The maximum speed of the bunch of bananas is v=44.0 cm/s=0.44 m/s.

Now we know the maximum speed

Now we know the period of the oscillation

Now the weight of the bunch of bananas is

The weight of the bananas in newtons is 32.39669421 N or 32.40 N approx.

genius_generous answered 2 years ago

Next > < Previous

Related Solutions

Which of the following statements are correct? A. All oscillatory motion is Simple Harmonic Motion. B....

Which of the following statements are correct? A. All oscillatory motion is Simple Harmonic Motion. B. Simple Harmonic motion is a special case of oscillatory motion. C. Oscillatory motion is a special case of Simple Harmonic motion. D. Oscillatory motion cannot be Simple Harmonic motion Which of the following statements is correct? A. In simple harmonic motion, kinetic energy is constant. B. In simple harmonic motion, potential energy is constant. C. In simple harmonic motion, the sum of kinetic and...

1.)How would you describe the motion of the pendulum? a.)Rotational Motion b.)Linear motion c.)Oscillatory Motion 2.)What...

1.)How would you describe the motion of the pendulum? a.)Rotational Motion b.)Linear motion c.)Oscillatory Motion 2.)What is the shape of the graph of position versus time for the pendulum? a.)Exponential b.)Sine Wave c.)Circular d.)Tangential 3.)What is the shape of the graph for position versus time for the spring? a.)Circular b.)Exponential c.)Sine Wave d.)Tangential 4.)What were the variables that were changed for the experiment? a.)Velocity of the weight b.)Temperature of the room c.)Mass of the weight d.)length of the pendulum 5.)Which...

What is the amplitude of the wing tip's motion?

We can model the motion of a bumblebee's wing as simple harmonic motion. A bee beats its wings 250 times per second, and the wing tip moves at a maximum speed of 2.5 m/s. Part A What is the amplitude of the wing tip's motion? Express your answer to two significant figures and include the appropriate units.

particle is in simple harmonic motion along the x axis. The amplitude of the motion is...

particle is in simple harmonic motion along the x axis. The amplitude of the motion is xm. When it is at x = x1, its kinetic energy is K = 5 J and its potential energy (measured with U = 0 at x = 0) is U = 3 J. When it is at x = −1 2x1, the kinetic and potential energies are: A. K = 5 J and U = 3J B. K = 5 J and U...

An electron undergoes an oscillatory circular motion in the xy plane, dictated by a uniform constant...

An electron undergoes an oscillatory circular motion in the xy plane, dictated by a uniform constant magnetic field B applied in the z direction, and by a circularly polarized electromagnetic wave that propagates in the z direction. The electric field of the wave is given by E = Eo[cos(kz - wt)x - sin(kz - wt)y]. Note that at z=0, where the electron moves, this electric field is E = Eo[cos(wt)x + sin(wt)y]. (a) This part of the problem is classical...

Consider the retail market for bananas in Australia in 2020. The market is in equilibrium with...

Consider the retail market for bananas in Australia in 2020. The market is in equilibrium with 20,000 tonnes being bought and sold per year at a price of $4 per kg. a. Explain why $5 per kg for bananas is not an equilibrium price. Given the current demand and supply, if the price was temporarily $5 per kg, explain how the market would return to equilibrium. b. Explain why the production/consumption of 20,000 tonnes of bananas is the socially efficient...

8. Does the period of a simple pendulum depend on the amplitude of its motion? Explain.

Question 1 Consider the retail market for bananas in Australia in 2020. The market is in...

Question 1 Consider the retail market for bananas in Australia in 2020. The market is in equilibrium with 20,000 tonnes being bought and sold per year at a price of $4 per kg. Question 21 (5 points) a. Label the diagram appropriately, by writing the labels i. to vii. Question 22 (6 points) b. Explain why $5 per kg for bananas is not an equilibrium price. Given the current demand and supply, if the price was temporarily $5 per kg,...

How to slove: Simple Harmonic Motion Amplitude = 10ᵒ m = 100.0 g Length =...

How to slove: Simple Harmonic Motion Amplitude = 10ᵒ m = 100.0 g Length = 1.000 m 0.850 m 0.700 m 0.550 m 0.400 m 0.250 m 0.100 m Trial t10 (s) T (s) t10 (s) T (s) t10 (s) T (s) t10 (s) T (s) t10 (s) T (s) t10 (s) T (s) t10 (s) T (s) 1 2 3 4 5 Average:

A bolt of mass 2.08×10?2 kg moves with simple harmonic motion that has an amplitude of...

A bolt of mass 2.08×10?2 kg moves with simple harmonic motion that has an amplitude of 0.243 m and a period of 1.480 s. The displacement of the bolt is 0.243 m when t = 0. (a) Find the displacement of the bolt at time t = 0.508 s. (b) Find the magnitude of the force acting on the bolt at time t = 0.508 s. (c) What is the minimum time required for the bolt to move from its...

Subjects