In: Statistics and Probability
of 17 Step 1 of 5 024550 The director of research and development is testing a new drug. She wants to know if there is evidence at the 0.1 level that the drug stays in the system for less than 336 minutes. For a sample of 16 patients, the mean time the drug stayed in the system was 330 minutes with a standard deviation of 25 . Assume the population distribution is approximately normal. Step 1 of 5: State the null and alternative hypotheses.
H0: = 336
Ha: < 336
The test statistic t = ()/(s/)
= (330 - 336)/(25/)
= -0.96
P-value = P(T < -0.96)
= 0.1761
As the P-value is greater than the significance level (0.1761 > 0.1), we should not reject the null hypothesis.
At 0.1 significance level there is not sufficient evidence to support the claim that the drug stays in the system for less than 336 minutes.