In: Statistics and Probability
Below are the hydrocarbon emissions at idling speed, (in parts per million, ppm) of a random sample of eighteen 1990 model cars.
39 135 40 152 41 153 62 162 70 185 81 260 103 302 110 328 132 332
Use the WSRT to determine if there is sufficient evidence to indicate that the median hydrocarbon emission at idling speed is under 180 ppm. (alpha = .05).
Ho:median=180
H1: median <180
treatment 1 | treatment2 | sign | abs difference | Rank | sign rank |
39 | 180 | -1 | 141 | 16 | -16 |
135 | 180 | -1 | 45 | 5 | -5 |
40 | 180 | -1 | 140 | 15 | -15 |
152 | 180 | -1 | 28 | 4 | -4 |
41 | 180 | -1 | 139 | 14 | -14 |
153 | 180 | -1 | 27 | 3 | -3 |
62 | 180 | -1 | 118 | 12 | -12 |
162 | 180 | -1 | 18 | 2 | -2 |
70 | 180 | -1 | 110 | 11 | -11 |
185 | 180 | 1 | 5 | 1 | 1 |
81 | 180 | -1 | 99 | 10 | -10 |
260 | 180 | 1 | 80 | 9 | 9 |
103 | 180 | -1 | 77 | 8 | -8 |
302 | 180 | 1 | 122 | 13 | 13 |
110 | 180 | -1 | 70 | 7 | -7 |
328 | 180 | 1 | 148 | 17 | 17 |
132 | 180 | -1 | 48 | 6 | -6 |
332 | 180 | 1 | 152 | 18 | 18 |
The sum of positive ranks is:=58
and the sum of negative ranks is:=113
test stat = min{W+,W- } = 58
The critical value for the signficance level α=0.05 provided, and n= 18 , the type of tail specified is T*=47, and the null hypothesis is rejected if T≤47.
since, T>47,do not reject Ho
hence, there is not sufficient evidence to indicate that the median hydrocarbon emission at idling speed is under 180 ppm.