Question

A cameraman on a pickup truck is traveling westward at 16 km/h while he videotapes a cheetah that is moving westward 31 km/h faster than the truck. Suddenly, the cheetah stops, turns, and then run at 50 km/h eastward, as measured by a suddenly nervous crew member who stands alongside the cheetah's path. The change in the animal's velocity takes 1.7 s. What are the (a) magnitude and (b) direction of the animal

Answer 1

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A cameraman on a pickup truck is traveling westward at 25 km/h?

while he videotapes a cheetah that is moving westward 33 km/h faster than the truckSuddenly, the cheetah stops, turns, and then run at 46 km/h eastward, as measured by a suddenly nervous crew member who stands alongside the cheetah's path. The change in the animal's velocity takes 2.0 s. What are the (a) magnitude of the cheetah's acceleration according to the cameraman and the (b) magnitude of the cheetah's acceleration according to the nervous crew member?

acceleration = ?v/?t Now assuming westward is positive, the cameramen sees an initail velocity of 33km/h*(1000m/km*1h/3600s) = 9.17m/s and
a final velocity of -(46+25)*1000/3600 = -19.72m/s

So for the cameraman a = (-19.72-9.17)/2.0 = -14.4m/s^2 so magnitude = 14.4m/s^2

For the stationary crew member vi = 58km/h*(1000/3600) = 16.11m/s
and a vf = -46*1000/3600 = -12.78m/s

So he sees an a = (-12.78-16.11)/2.0s = -14.4m/s^2 (magnitude 14.4m/s^2)