Question

For this question, you must show all work to receive any credit.
DONOT USE MATLAB FOR THIS QUESTION.

for k = 3*1:6:21
j = k/3;
if rem(j,6) >= 3
disp(k)
elseif rem(j,3) < 2
disp(j)
else
disp(3)
end
end

write out the solution

Answer 1

Here I am giving an explanation for the code:
Firstly for loop is given as

k=3*1:6:21 => k=3:6:21 =>k=3,3+6,3+6+6,21 => k=3,9,15,21.

So for loop is iterated 4 times with k= k=3,9,15,21.

Next j=k/3

So j becomes j=1,3,5,7(3/3,9/3,15/3,21/3) after iterationg for loop j changes from starting to ending value.

So loop repeats 4 times

First for k=3 and j=1:

if rem(j,6)>=3

rem(1,6)=1/6 remainder is 1 which is not true so it goes to next ifelse

rem(j,3)<2

rem(j,3)=1 it is less than 2 hence,True. So this ifelse executes and disp(j) is exuted and 1 is shown in output.

Second for k=9 and j=3:

if rem(j,6)>=3

rem(3,6)=3/6 remainder is 3 which is true. So this if executes and disp(k) is exuted and 9 is shown in output.

Thirdly for k=15 and j=5:

if rem(j,6)>=3

rem(5,6)=5/6 remainder is 5 which is true. So this if executes and disp(k) is exuted and 15 is shown in output.

Finally for k=21 and j=7:

if rem(j,6)>=3

rem(7,6)=21/6 remainder is 1 which is not true so it goes to next ifelse

rem(j,3)<2

rem(7,3)=1 it is less than 2 hence,True. So this ifelse executes and disp(j) is exuted and 7 is shown in output.

So output is:
1

9

15

7