Question

Memory was allocated initially for 5 elements, later on two more elements added to list. How can
space be managed in such case. Implement the scenario in C.
IN C PROGRAMING

Answer 1

CODE:

#include <stdio.h>

#include <stdlib.h>

int main(void) {

  int *ptr;

  // a dynamic array of size 5 is allocated

  ptr = (int*) malloc(5 * sizeof(int));

  for(int i = 0; i < 5; ++i){

    // storing index+1 in the array

    *(ptr+i)=i+1;

  }

  printf("%d\n",*(ptr+4));

  // now for example assume 5 is a bit short for us

  // so lets extend the size of ptr array

  ptr = realloc(ptr, 7 * sizeof(int));

  // now we can store value till index 7

  for(int i = 0; i < 7; ++i){

    // storing index+1 in the array

    *(ptr+i)=i+1;

  }

  printf("%d\n",*(ptr+6));

return 0;

}

OUTPUT:

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