Question

In: Computer Science

Create using Java Description: Palindrome -- According to wikipedia "A palindrome is a word, phrase, number...

Create using Java

Description: Palindrome -- According to wikipedia "A palindrome is a word, phrase, number or other sequence of units that can be read the same way in either direction"
Write a application that can determine if a 5 digit number you input is a palindrome. If the number is a palindrome then print "The number is a palindrome." If it is not then print "The number is NOT a palindrome"
Make sure to use an array

  1. Allow input of any length integer (ie 12345654321 would be valid input)
  2. Allow input of any number of any alphanumeric characters (ie abg345tghtriu8 would be valid input)

//-----------------------------------
// This is the good version pseudocode
//   create string sInput
//
//   prompt for input
//
//   create char array (cArray) and assign sInput.toCharArray()
//
//   loop to check for palindrome (set i = 0, j = sInput.length()-1, check to see if i != j; increment i, decrement j)
//       check to see if current array values are !=
//           print not a palindrome
//           return
//       end of loop
//   print is a palindrome
//------------------------------

Solutions

Expert Solution

input code:

output:

code:

import java.util.*;
public class Main
{
   public static void main(String[] args)
   {
   /*declare the variables*/
       Scanner sc=new Scanner(System.in);
       /*take input from user*/
       System.out.print("Enter the String: ");
       String sInput=sc.next();
       /*declare the Character array*/
       char cArray[]=new char[sInput.length()];
      
       /*assign value into the Character array*/
       for(int i=0;i<sInput.length();i++)
   {
   cArray[i]=sInput.charAt(i);
   }
   int j=sInput.length(),count=0;
   /*check if string is Palindrome or not*/
   for(int i=0;i<sInput.length();i++)
   {
   /*if not match than break the loop*/
   if(cArray[i]!=cArray[j-i-1])
   {
   count=1;
   break;
   }
   }
   /*print according to the counter*/
   if(count==0)
   {
   System.out.println("Palindrome");
   }
   else
   {
   System.out.println("Not Palindrome");
   }
      
   }
}


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