Question

c++

give ways of filling array of uniform random numbers

Answer 1

1) Array of random numbers using C++ program,

Create an array:

int my_array[100];. Seed the random number generator srand(0​);.

Loop over your array and fill it up!:

int i;

for (i = 0; i < 100; i++)

try to get a 20 element array to fill with random numbers from rand. I was told using % 99 is 100 since the count starts at 0. Test and using brackets and +1 with my array increments the array to the next value and doesn't add 1.

2) Fill array with random numbers, Simple programming task - fill array with random integer values. We need to include time. h to Duration: C++ library has a function that generates random numbers, called the rand() function.

code:

#include<iostream>
#include<stdlib.h>
#include<time.h>
using namespace std;
int main()
{
srand(time(NULL));
const unsigned int sizeOfArray =10;
int numberArray[sizeOfArray];

for(int i=0;i<sizeOfArray;i++)
{
numberArray[i]=rand()%50;
cout<<numberArray[i]<<endl;
}
numberArray[0]=500;
numberArray[9]=1000;

for(int i=0; i<sizeOfArray ; i++)
{
cout<<numberArray[i]<<endl;
}

system("PAUSE");
return 0;
}

output:

13
42
5
22
46
36
22
10
46
35
500
42
5
22
46
36
22
10
46
1000

code(SS):

output(SS):

This is ways of filling array of uniform random numbers.