Question

IN C LANGUAGE ONLY PLEASE!

First Program:

1. create branchloop.c file
2. Content of the program
   1. Enter your name while running your program as you did with hello2.c (using argc and argv) name has to be 2 words max (e.g. Jose Lopez, Maria Rodrigues) . Make sure to check properly.
   2. Print your name 10 times using a loop. 10 is a fixed number.
   3. Count how many characters are in your first name and last name.
   4. If the number of characters of your first name is greater than last name print my first name is bigger than my last name.
   5. If the number of characters of your first name is less than last name then print my last name is bigger than my first name.
   6. If the number of characters is equal then print my first and last name have the same number of characters.
3. Compile the program using: gcc -o branchloop branchloop.c
4. Run the program using: ./branchloop firstname lastname

Second Program:

1. Copy branchloop.c to branchloop2.c
2. Restructure program to add the following functionality
3. Enter a number at command line representing an index to your name along with your name. e.g. ./branchloop2 carlos alonso 5
4. The index number must be within the size of your full name - if is not an error should be provided (number is larger than your full name).
5. If the number fits the length of your name, use the number to find the letter correspond to it by indexing.
6. Finally print your name in all lower case, print index number, and print character indexed in upper case.

Third program:

1. Copy branchloop2.c to branchloop3.c
2. Use the number entered in command line to:
   1. Print your name that many times
   2. Use a Do-While loop
3. Count the number of letters in your name.
4. Print the number of characters in your name followed by your name backwards.

Answer 1

First Program -

Code -

#include <stdio.h>

int main( int argc, char *argv[] ) {
//print name 10 time using for loop
for(int i = 0 ; i < 10; i++)
//argv[1] is first name and argv[2] is last name
printf("%s %s\n", argv[1],argv[2]);

//count character in first name   
int firstNameCharCount = 0;
//using for loop iterate till argv[1][i] not equal to '\0'
for (int i = 0; argv[1][i] != '\0'; ++i)
//incremenet firstNameCharCount
firstNameCharCount++;
//similarly count char in second name
int secondNameCharCount = 0;
for (int i = 0; argv[2][i] != '\0'; ++i)
secondNameCharCount++;
  
//compare character count , if firstNameCharCount is greater than secondNameCharCount
//then print my first name is bigger than my last name
if(firstNameCharCount>secondNameCharCount){
printf("my first name is bigger than my last name");
}
//compare character count , if secondNameCharCount is greater than firstNameCharCount
//then print my last name is bigger than my first name
else if(firstNameCharCount<secondNameCharCount){
printf("my last name is bigger than my first name");
}
//if both are equal
else if(firstNameCharCount==secondNameCharCount){
printf("my first and last name have the same number of characters.");
}
  
  

}

Screenshots -

pls ask multiple question in different part , we are told to answer first only in case of multiple question , pls do give a like ,thank you