Question

In: Math

Contracts for two construction jobs are randomly assigned to one or more of three firms A,...

Contracts for two construction jobs are randomly assigned to one or more of three firms A, B, and C. Let Y1 denote the number of contracts assigned to firm A and Y2 the number of contracts assigned to firm B. Recall that each firm can receive 0, 1 or 2 contracts.

(a) Find the joint probability function for Y1 and Y2.

(b) Find the marginal probability of Y1 and Y2.

(c) Are Y1 and Y2 independent? Why?

(d) Find E(Y1 − Y2).

(e) Find Cov(Y1, Y2)

Solutions

Expert Solution

There are three firms. Job is randomly assigned to one of the firms randomly i.e

Probability of a job assigned to one of the given firms =1/3

Probability of assigning two jobs to any of the firms =(1/3)(1/3)=1/9

(Example : Probability of assigning first job to Firm A and second job firm B =1/3x1/3=1/9 ; Similarlry ,

Probability of assigning first job to Firm C and second job firm B =1/3 x 1/3 =1/9...so on)

(a) Joint Probability function of Y1, Y2

(b)

Marginal Probability of Y1

Marginal of Y2 =

(c)

Therefore, Y1 and Y2 are independent

(d)

E(Y1-Y2) = E(Y1)-E(Y2)

E(Y1-Y2) = E(Y1)-E(Y2) =1-1=0

E(Y1-Y2) = 0

(e)

As Y1, Y2 are independent,

E(Y1Y2) = E(Y1)E(Y2)

Cov(Y1Y2) = E(Y1Y2) - E(Y1)E(Y2) = 0

Cov (Y1Y2) = 0

(In can be observed that,

E(Y1Y2) =1

E(Y1)=1

E(Y2)=1

Cov(Y1Y2) = E(Y1Y2) - E(Y1)E(Y2) =1-1x1 =1-1=0

Cov(Y1,Y2) =0


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