In: Statistics and Probability
) For an effective parental skill study, a researcher asked: How many hours do your kids watch the television during a typical week in Barcelona? The mean of 100 Kids (ages 6-11) spend about 28 hours a week in front of the TV. Suppose the study follows a normal distribution with standard deviation 5.
a) Estimate the mean of all kids (ages 6-11) in Barcelona, using 99% confidence interval. (show all the calculations)
b) Write the conclusion of your result
Solution :
Given that,
Point estimate = sample mean = = 28
sample standard deviation = s = 5
sample size = n = 100
Degrees of freedom = df = n - 1 = 100 -1 =99
At 99% confidence level
= 1-0.99% =1-0.99 =0.01
/2
=0.01/ 2= 0.005
t/2,df
= t0.005,99 = 2.63
t /2,df = 2.63
Margin of error = E = t/2,df * (s /n)
= 2.63 * ( 5/ 100)
Margin of error = E = 1.31
The 99% confidence interval estimate of the population mean is,
- E < < + E
28 -1.31 < < 28 + 1.31
26.69 < < 29.31
(26.69,29.31)
The kids watch the television during a typical week in Barcelona is 26.69 and 29.31 hours.