Two charges are located in the ?x–?y plane. If ?1=−3.35 nCq1=−3.35 nC and is located at...

Two charges are located in the ?x–?y plane. If ?1=−3.35 nCq1=−3.35 nC and is located at (?=0.00 m,?=0.840 m)(x=0.00 m,y=0.840 m), and the second charge has magnitude of ?2=3.00 nCq2=3.00 nC and is located at (?=1.20 m,?=0.650 m)(x=1.20 m,y=0.650 m), calculate the ?x and ?y components, ??Ex and ??Ey, of the electric field, ?⃗ E→, in component form at the origin, (0,0)(0,0). The Coulomb force constant is 1/(4??0)=8.99×109 N⋅m2/C21/(4πϵ0)=8.99×109 N⋅m2/C2.

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Expert Solution

As q1 is negative charge, electric field due to q1 at origin is along +Y direction and as q2 is positive charge, electric field due to q2 is directed toward BO vector as shown in the figure.

genius_generous answered 1 year ago

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