Question

Homework – Zeller’s Algorithm Pt2

Zeller’s algorithm computes the day of the week on which a given date will fall (or fell). You are provided this algorithm in CANVAS. In this task, you must transform the provided solution to a “Defined Function”

Function Name

zelleralg

Input Parameters	• month • day • year
Return Values	The result from the algorithm. This is a number (0-6) that corresponds to the day of the week, where 0 represents Sunday, 1 is Monday, . . ., 6 is Saturday.

Information collected from the input NONE (all user inputs from MAIN script) command
Output to the screen NONE (all outputs printed from MAIN script)

On the main script, welcome the user, ask for his/her name, and DOB (date of birth). Then call the “defined function” and print-out a formatted output.

   

USER INPUT

USER INPUT

FORMATTED OUTPUT

Finally ask if the user if he/she wants to RERUN. If yes, loop your code all-over. If not, just display a goodbye message.

]

(Below is the solution for the code. you just have to develop the user defined function and the rest of the instructions are above. when finished it should look like the larger text)

clear

clc

% Welcome message

fprintf('Welcome. This program uses the Zeller''s algorithm to compute\n')

fprintf('the day of the week for a given date. Outputs are given as\n')

fprintf('numbers between 0 - 6:\n')

fprintf('(0) - Sun \t(1)- Mon \t(2)- Tue \t(3)- Wed \t(4)- Thu \t(5)- Fri')

fprintf('\t(6)- Sat\n')

fprintf('\nINPUT THE DATE:\n')

% Input section

Month = input('Month: ');

Day = input('Day: ');

Year = input('Year: ');

% A = 1 plus the remainder of (the month number plus 9) divided by 12

A = 1+mod(Month+9,12);

% B = the day of the month

B = Day;

% C = the year of the century PLUS the ROUND DOWN from the equation: (0.09*Month-

0.27).

C = (mod( Year , 1000 ))+floor(0.09*Month-0.27);

%D = the century

D = floor( Year / 100 );

% Additional integers necessary for the calculation

W = floor((13*A-1)/5);

X = floor(C/4);

Y = floor(D/4);

Z = W+X+Y+B+C-2*D;

% R is the day of the week, where 0 represents Sunday, 1 is Monday, . . ., 6 is

Saturday

R = mod( Z, 7 );

fprintf('\nOUTPUT:\n')

fprintf('%d/%d/%d = %d\n', Month, Day, Year, R );

Answer 1

% zelleralg function

function R = zelleralg(Month, Day, Year)
% A = 1 plus the remainder of (the month number plus 9) divided by 12
A = 1+mod(Month+9,12);

% B = the day of the month
B = Day;

% C = the year of the century PLUS the ROUND DOWN from the equation: (0.09*Month-0.27).
C = (mod( Year , 1000 ))+floor(0.09*Month-0.27);

%D = the century
D = floor( Year / 100 );

% Additional integers necessary for the calculation
W = floor((13*A-1)/5);
X = floor(C/4);
Y = floor(D/4);
Z = W+X+Y+B+C-2*D;

% R is the day of the week, where 0 represents Sunday, 1 is Monday, . . ., 6 is Saturday
R = mod( Z, 7 );

end

//////////////////////////////////////////////////////////////////////////////////////////////////////////////////////////////////////////////////////////

% MAIN script

clear
clc

% Welcome message
fprintf('Welcome. This program uses the Zeller''s algorithm to compute\n')
fprintf('the day of the week for a given date. Outputs are given as\n')
fprintf('numbers between 0 - 6:\n')
fprintf('(0) - Sun \t(1)- Mon \t(2)- Tue \t(3)- Wed \t(4)- Thu \t(5)- Fri')
fprintf('\t(6)- Sat\n')
fprintf('\nINPUT THE DATE:\n')

% Input section
Month = input('Month: ');
Day = input('Day: ');
Year = input('Year: ');

% function zelleralg called
R = zelleralg(Month, Day, Year)

% print the output
fprintf('\nOUTPUT:\n')
fprintf('%d/%d/%d = %d\n', Month, Day, Year, R );

////////////////////////////////////////////////////////////////////////////////////////////////////////////////////////////////////////////

Output:

Welcome. This program uses the Zeller's algorithm to compute
the day of the week for a given date. Outputs are given as
numbers between 0 - 6:
(0) - Sun (1)- Mon (2)- Tue (3)- Wed (4)- Thu (5)- Fri (6)- Sat

INPUT THE DATE:
Month: 3
Day: 31
Year: 2020
R = 2

OUTPUT:
3/31/2020 = 2