Question

In a study designed to prepare new gasoline-resistant coatings, a polymer chemist dissolves 6.077 g poly(vinyl alcohol) in enough water to make 100.0 mL of solution. At 25

Answer 1

We know that =CRT

Where

= osmotic pressure = 0.275 atm

C = concentration = ?

R = gas constant = 0.0821 Latm/mol-K

T = Temperature in kelvin = 25 ^oC = 25 + 273 = 298 K

Plug the values we get C = /RT

                                       = 0.275 / ( 0.0821 x 298)

                                      = 0.0112 mol/L

We have Concentration , C = ( mass/molarmass ) / Volume in L

Given mass of polymer = 6.077 g

Volume of the solution = 100.0 m:L = 0.1 L

Plug the values we have

                     0.0112 mol / L = ( 6.077 g / Molarmass ) / 0.1 L

                     Molar mass = 5406.5 g/mol