Question

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Use the following to answer 5 - 8. Among the four northwestern states, Washington has 51%...

Use the following to answer 5 - 8.

Among the four northwestern states, Washington has 51% of the total population, Oregon has 30%, Idaho has 11%, and Montana has 8%. A market researcher selects a sample of 1000 subjects, with 450 in Washington, 340 in Oregon, 150 in Idaho, and 60 in Montana. At the .05 significance level, test the claim that the sample of 1000 subjects has distribution that agrees with the distribution of state populations.

5.) Which of the following is the correct statement for the claim?

H1: Wa = .51, Or = .3, Id = .11, Mn= .08
Ho: At least one of the percentages is different
H1: At least one of the percentages is different.
Ho: Wa = .51, Or = .3, Id = .11, Mn= .08

6.) The test statistic is:

33.942
31.938
26.963
17.455

7.) The p-value is:

.000000238
.000000539
.000000989
.263122245

8.) The conclusion for this test is:

Fail to reject Ho which says there is sufficient evidence to warrant rejection of the claim of the same distribution
Reject Ho which says there is sufficient evidence to support the claim of the same distribution
Fail to reject Ho which says that there is sufficient evidence to support the claim of the same distribution
Reject Ho which says there is sufficient evidence to warrant rejection of the claim of the same distribution

Solutions

Expert Solution

5.) Which of the following is the correct statement for the claim?


H1: At least one of the percentages is different.

6.) The test statistic is: 31.938

Test statistic formula is given as below:

Chi square = ∑[(O – E)^2/E]

Where, O is observed frequencies and E is expected frequencies.

State

%

O

E

(O - E)^2/E

Washington

0.51

450

510

7.059

Oregon

0.3

340

300

5.333

Idaho

0.11

150

110

14.545

Montana

0.08

60

80

5.000

Total

1

1000

1000

31.938

Chi square = ∑[(O – E)^2/E]

Chi square = 31.938

7.) The p-value is: 0.000000539

We have n=4, df = n – 1 = 4 – 1 = 3

P-value = 0.000000539

(by using Chi-square table or excel)

8.) The conclusion for this test is:

Here, we get

P-value = 0.000000539 < α = 0.05

So, we reject the null hypothesis H0

Reject Ho which says there is sufficient evidence to warrant rejection of the claim of the same distribution


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