Question

in C++, Write a program that asks the user to enter 6 numbers. Use an array to store these numbers. Your program should then count the number of odd numbers, the number of even numbers, the negative, and positive numbers. At the end, your program should display all of these counts. Remember that 0 is neither negative or positive, so if a zero is entered it should not be counted as positive or negative. However, 0 is an even number.

Sample Run:

Enter 10 numbers
2
3
-3
6
-1
0
You entered:
3 odd numbers
3 even numbers
2 negative numbers
3 positive numbers

Answer 1

Program:

#include <iostream>

using namespace std;

int main()
{
    int n = 6, num_array[6];
    int even_count = 0, odd_count = 0;
    int positive_count = 0, negative_count = 0;
    
    cout << "Enter 6 numbers" << endl;
    for (int i = 0; i < n;i++) {
        // Taking input 6 numbers and adding to array
        cin >> num_array[i];
        
        // If condition to check positive number
        if (num_array[i] > 0) {
            positive_count++; // Increment positive count
        } else if (num_array[i] < 0) { // condition to check negative number
            negative_count++; // Increment negative count
        }
        
        // If condition to check for even number
        if (num_array[i]%2 == 0) {
            even_count++; //Increment even count
        } else { // If number is not even
            odd_count++; // Increment odd count
        }
    }
    
    // Printing output count of odd,even,negative,positive numbers
    cout << odd_count << " odd numbers" << endl;
    cout << even_count << " even numbers" << endl;
    cout << negative_count << " negative numbers" << endl;
    cout << positive_count << " positive numbers" << endl;

    return 0;
}

Output: