Write up a formal proof that the angle bisectors of a triangle
are concurrent, and that the point of concurrency (the incenter) is
equidistant from all three sides.
Show that in any triangle the angle bisectors are concurrent.
The point where they meet is called the incenter of the
triangle, and is the center of the incircle, whose radius
is the distance from the incenter to any of the sides of the
triangle.
Prove the following using the triangle inequality:
Given a convex quadrilateral, prove that the point determined by
the intersection of the diagonals is the minimum distance point for
the quadrilateral - that is, the point from which the sum of the
distances of the vertices is minimal.
PROVE THE FOLLOWING RESULT: Using a compass and a straightedge,
construct a triangle ABC such that side BC is of length 2, the
circumradius is of length 3/2 and the median AA' is of length 2 and
is the midpoint of BC.