In: Physics
An Escort and a Camaro traveling at right angles collide and stick together. The Escort has a mass of 1200 kg and a speed of 20 km/h in the positive x direction before the collision. The Camaro has a mass of 1500 kg and was traveling in the positive y direction. After the collision, the two move off at an angle of 57 o to the x axis. What was the speed of the Camaro?(in km/h)
m1 = 1200 kg m2 = 1500 kg
speeds before collision
u1x = 20
Km/h
u1y = 0
u2x = 0 u2y = ?
speeds after collision
v1x = v2x = V*cos57
v1y = v2y = V*cos57
initial momentum before collision
Pix = m1*u1x + m2*u2x
after collision final momentum
Pfx = m1*v1x + m2*v2x
from moentum conservation
total momentum is conserved
from momentum conservation total momentum is
conserved
Pfx = Pix
m1*u1x + m2*u2x = m1*v1x + m2*v2x
(1200*20) + (1500*0) = (1200+1500)*v*cos57.....(1)
v = 16.32 m/s
Pfy = Piy
m1*u1y + m2*u2y = m1*v1y + m2*v2y
(1200*0) + (1500*u2y) = (1200+1500)*16.32*sin57.....(1)
u2y = 24.64 km/h <<--answer