In: Statistics and Probability
You wish to test the following claim (HaHa) at a significance
level of α=0.005α=0.005. For the context of this problem,
μd=μ2−μ1μd=μ2-μ1 where the first data set represents a pre-test and
the second data set represents a post-test.
      Ho:μd=0Ho:μd=0
      Ha:μd>0Ha:μd>0
You believe the population of difference scores is normally
distributed, but you do not know the standard deviation. You obtain
the following sample of data:
| pre-test | post-test | 
|---|---|
| 48.6 | 37.2 | 
| 53 | 73.8 | 
| 69.1 | 78.9 | 
| 43.7 | 35.4 | 
| 51.7 | 50.9 | 
| 48.3 | 38.7 | 
| 54.7 | 58.1 | 
| 39.5 | 47.1 | 
| 62.7 | 72.1 | 
| 53.2 | 44.5 | 
| 58.6 | 64 | 
| 62.7 | 66.5 | 
| 56 | 60.9 | 
| 67.3 | 64 | 
| 51.4 | 45.9 | 
| 44.2 | 34.6 | 
| 53.2 | 48.3 | 
| 62.7 | 63.6 | 
| 40.2 | 40.9 | 
| 48.9 | 57.7 | 
| 51.1 | 33.3 | 
| 45.5 | 35.3 | 
| 40.9 | 44.1 | 
| 60.8 | 56.2 | 
| 58.1 | 59.8 | 
What is the test statistic for this sample? (Report answer accurate
to three decimal places.)
test statistic =
What is the p-value for this sample? (Report answer accurate to
four decimal places.)
p-value =
| pre-test | post-test | d = Post-test - Pre-test | 
| 48.6 | 37.2 | -11.4 | 
| 53 | 73.8 | 20.8 | 
| 69.1 | 78.9 | 9.8 | 
| 43.7 | 35.4 | -8.3 | 
| 51.7 | 50.9 | -0.8 | 
| 48.3 | 38.7 | -9.6 | 
| 54.7 | 58.1 | 3.4 | 
| 39.5 | 47.1 | 7.6 | 
| 62.7 | 72.1 | 9.4 | 
| 53.2 | 44.5 | -8.7 | 
| 58.6 | 64 | 5.4 | 
| 62.7 | 66.5 | 3.8 | 
| 56 | 60.9 | 4.9 | 
| 67.3 | 64 | -3.3 | 
| 51.4 | 45.9 | -5.5 | 
| 44.2 | 34.6 | -9.6 | 
| 53.2 | 48.3 | -4.9 | 
| 62.7 | 63.6 | 0.9 | 
| 40.2 | 40.9 | 0.7 | 
| 48.9 | 57.7 | 8.8 | 
| 51.1 | 33.3 | -17.8 | 
| 45.5 | 35.3 | -10.2 | 
| 40.9 | 44.1 | 3.2 | 
| 60.8 | 56.2 | -4.6 | 
| 58.1 | 59.8 | 1.7 | 
| μd = | -0.572 | |
| s = | 8.670713158 | 
(a)
Data:
n = n1 = n2 = 25
μd = -0.572
s = 8.670713158
Hypotheses:
Ho: μd ≤ 0
Ha: μd > 0
Decision Rule:
α = 0.05
Degrees of freedom = 25 - 1 = 24
Critical t- score = 1.710882067
Reject Ho if t > 1.710882067
Test Statistic:
SE = s/√n = 8.67071315790499/√25 = 1.734142632
t = μd/SE = -0.572000000000001/1.734142631581 = -0.330
(b)
p- value = 0.3722
Decision (in terms of the hypotheses):
Since -0.329845994 < 1.711 we fail to reject Ho
Conclusion (in terms of the problem):
There is no sufficient evidence that μd > 0
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