Question

In: Physics

A chimney (length 17.6 m, mass 823 kg] cracks at the base and topples. Assume: -...

A chimney (length 17.6 m, mass 823 kg] cracks at the base and topples. Assume: - the chimney behaves like a thin rod, and does not break apart as it falls. - only gravity (no friction) acts on the chimney as it falls. - the bottom of the chimney pivots, but does not move. Find the linear speed of the center of mass of the chimney, in m/s, just as it hits the ground

Part 2)A chimney (length 11.1 m, mass 852 kg] cracks at the base and topples. Assume: - the chimney behaves like a thin rod, and does not break apart as it falls. - only gravity (no friction) acts on the chimney as it falls. - the bottom of the chimney pivots, but does not move. Find the linear speed of the very top of the chimney, in m/s, just as it hits the ground.

Solutions

Expert Solution

Part 1

The change in potential energy of the centre of mass of the rod will be equal to the change in rotational kinetic energy of the rod.

where is the moment of inertia of a rod pivoted at a point and is equal to .

Substituting the required values, we get

Now that we know the angular velocity, we can find the linear velocity of the required point, which is just the angular velocity times the point's distance from the centre.

Part 2

We know that for a falling rod, the angular velocity is

Substituting our values for this rod, we get

The velocity of the top end will be


Related Solutions

QUESTION 14 A chimney (length 18 m, mass 980 kg] cracks at the base and topples.  Assume:...
QUESTION 14 A chimney (length 18 m, mass 980 kg] cracks at the base and topples.  Assume: - the chimney behaves like a thin rod, and does not break apart as it falls. - only gravity (no friction) acts on the chimney as it falls. - the bottom of the chimney pivots, but does not move. Find the linear speed of the very top of the chimney, in m/s, just as it hits the ground.   QUESTION 15 A 23 kg cart...
Please answer both questions 1) A chimney (length 24.2 m, mass 401 kg) cracks at the...
Please answer both questions 1) A chimney (length 24.2 m, mass 401 kg) cracks at the base and topples. Assume: the chimney behaves like a thin rod, and does not break apart as it falls, only gravity (no friction) acts on the chimney as it falls, the bottom of the chimney pivots, but does not move. Find the linear speed of the center of mass of the chimney, in m/s, just as it hits the ground 2)A chimney (length 13...
A pendulum has a length 1 m and a mass 1 kg. Assume Earth free fall...
A pendulum has a length 1 m and a mass 1 kg. Assume Earth free fall acceleration equal to 10 m/s^2. When the pendulum oscillates, the maximal deflection angle is +/-1 degree. 1.Suppose the pendulum started losing energy at the rate 1% per period. As a result, the energy of the pendulum drops according to E(t)= E(t=0)*exp(-z*t). Let’s call z damping constant, it has units 1/sec. a) Find Z b) Sketch E(t) for the time span of a few hundred...
A pendulum has a length 1 m and a mass 1 kg. Assume Earth free fall...
A pendulum has a length 1 m and a mass 1 kg. Assume Earth free fall acceleration equal to 10 m/s^2. When the pendulum oscillates, the maximal deflection angle is +/- 1 degree. a) If the maximal deflection angle doubles, what would be the new period? b) If the pendulum mass goes up 100 times, what would be the new period? c) If the length goes up 100 times, what would be the period? d) If the pendulum moves to...
A pendulum has a length 1 m and a mass 1 kg. Assume Earth free fall...
A pendulum has a length 1 m and a mass 1 kg. Assume Earth free fall acceleration equal to 10 m/s^2. When the pendulum oscillates, the maximal deflection angle is +/- 1 degree. a) How long will it take before the energy drops to half of the initial value at t=0? b) How long will it take before the max deflection angle drops to half of the initial value at t=0? c) If the damping was produced by a force...
A ladder of length L = 2.3 m and mass m = 14 kg rests on...
A ladder of length L = 2.3 m and mass m = 14 kg rests on a floor with coefficient of static friction μs = 0.54. Assume the wall is frictionless. A person with mass M = 69 kg now stands at the very top of the ladder. What is the normal force the floor exerts on the ladder? What is the minimum angle to keep the ladder from sliding?
A ladder of length L = 2.8 m and mass m = 16 kg rests on...
A ladder of length L = 2.8 m and mass m = 16 kg rests on a floor with coefficient of static friction ?s = 0.51. Assume the wall is frictionless. 1) What is the normal force the floor exerts on the ladder? 2) What is the minimum angle the ladder must make with the floor to not slip? 3) A person with mass M = 69 kg now stands at the very top of the ladder. What is the...
A simple pendulum has a mass of 0.550 kg and a length of 2.00 m. It...
A simple pendulum has a mass of 0.550 kg and a length of 2.00 m. It is displaced through an angle of 11.0
A simple pendulum has a mass of 0.650 kg and a length of 7.00 m. It...
A simple pendulum has a mass of 0.650 kg and a length of 7.00 m. It is displaced through an angle of 14.0° and then released. Using the analysis model of a particle in simple harmonic motion, calculate the following. (Give your answer to the thousandths place.) (a) What is the maximum speed of the bob? (b) What is the maximum angular acceleration of the bob? (rad/s2) (c) What is the maximum restoring force of the bob? (d) Solve parts...
A simple pendulum with mass m = 1.6 kg and length L = 2.79 m hangs...
A simple pendulum with mass m = 1.6 kg and length L = 2.79 m hangs from the ceiling. It is pulled back to an small angle of θ = 10.7° from the vertical and released at t = 0. A)What is the period of oscillation? B)What is the magnitude of the force on the pendulum bob perpendicular to the string at t=0? C)What is the maximum speed of the pendulum? D)What is the angular displacement at t = 3.62...
ADVERTISEMENT
ADVERTISEMENT
ADVERTISEMENT