1. Lead oxide may be reduced according to the following: PbO2(s) + 4H+ + 2e- =...

1. Lead oxide may be reduced according to the following: PbO2(s) + 4H+ + 2e- = 2H2O + Pb2+ Eo = 1.55 V After a solution of PbO2 is aerated (pO2 = 0.21 atm, pe = 20.75) for a period of time it is observed that Pb2+ = 10-4 mole/L. What is the pH of the solution? Note: pe = Eo / 0.059. (5 points)

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Amanda K answered 3 months ago

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