as best as i can determine from a chart from the centers for disease control, the...

as best as i can determine from a chart from the centers for disease control, the mean weight for 6 year old American boys is about 50 pounds with a standard deviation of 15 pounds. Assume weights are distributed normally for this problem. what is the probability that two random 6 year old boys will together weigh more than a random thirteen year old boy?

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Expert Solution

Solution :

Given that ,

mean = $\mu$ = 50

standard deviation = = 15

n = 2

= $\mu$ = 50 and

= / n = 15 / 2 = 10.6066

P( > 13) = 1 - P( < 13)

= 1 - P(( - ) / < (13-50) / 10.6066)

= 1 - P(z < -3.49) using z table

= 1 - 0.0002

= 0.9998

Probability = 0.9998

orchestra answered 2 years ago

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