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A solution of household bleach contains 5.25% sodium hypochlorite, NaOCl, by mass. Assuming that the density...

A solution of household bleach contains 5.25% sodium hypochlorite, NaOCl, by mass. Assuming that the density of bleach is the same as water, calculate the volume in mL of household bleach that should be diluted with water to make 500.0 mL of a pH = 9.80 solution.

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queen_honey_blossom answered 6 months ago
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A solution of household bleach contains 5.25% sodium hypochlorite, NaOCl, by mass. Assuming that the density...
A solution of household bleach contains 5.25% sodium hypochlorite, NaOCl, by mass. Assuming that the density of bleach is the same as water, calculate the volume of household bleach that should be diluted with water to make 500.0 mL of a pH = 10.00 solution. Use the Ka of hypochlorous acid found in the chempendix. (4.0e-8)
A solution of household bleach contains 5.25% sodium hypochlorite, NaOCl, by mass. Assuming that the density...
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A solution of household bleach contains 5.25% sodium hypochlorite, NaOCl, by mass. Assuming that the density of bleach is the same as water, calculate the volume of household bleach that should be diluted with water to make 500.0 mL of a pH = 10.00 solution. Use the Ka of hypochlorous acid found in the chempendix.Ionization Constants Acids Acid Formula Ionization Constant Ka Acetic CH3COOH 1.8×10–5 Arsenic H3AsO4 5.5×10–3 Benzoic C6H5COOH 6.3×10–5 Boric H3BO3 5.4×10–10 Butanoic C3H7COOH 1.5×10–5 Carbonic H2CO3 Ka1...
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A solution of household bleach contains 5.25% sodium hypochlorite, NaOCl, by mass. Assuming that the density of bleach is the same as water, calculate the volume (in mL) of household bleach that should be diluted with water to make 500.0 mL of a pH = 10.18 solution.
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A solution of household bleach contains 5.25% sodium hypochlorite, NaOCl, by mass. Assuming that the density of bleach is the same as water, calculate the volume of household bleach that should be diluted with water to make 500.0 mL of a pH = 10.18 solution.
A solution of household bleach contains 5.25% sodium hypochlorite, NaOCl, by mass. Assuming that the density...
A solution of household bleach contains 5.25% sodium hypochlorite, NaOCl, by mass. Assuming that the density of bleach is the same as water, calculate the volume of household bleach that should be diluted with water to make 500.0 mL of a pH = 10.18 solution. = _________ mL
A solution of household bleach contains 5.25% sodium hypochlorite, NaOCl, by mass. Assuming that the density...
A solution of household bleach contains 5.25% sodium hypochlorite, NaOCl, by mass. Assuming that the density of bleach is the same as water, calculate the volume of household bleach that should be diluted with water to make 500.0 mL of a pH = 10.10 solution.
A solution of household bleach contains 5.25% sodium hypochlorite, NaOCl, by mass. Assuming that the density...
A solution of household bleach contains 5.25% sodium hypochlorite, NaOCl, by mass. Assuming that the density of bleach is the same as water, calculate the volume of household bleach that should be diluted with water to make 500.0 mL of a pH = 10.00 solution. Use the K a of hypochlorous acid found in the chempendix.
Bleach (sodium hypochlorite, NaOCl) is produced by the reaction of a sodium hydroxide solution with chlorine...
Bleach (sodium hypochlorite, NaOCl) is produced by the reaction of a sodium hydroxide solution with chlorine gas. Water and NaCl are also produced in the reaction. 1.75 liters of a 45% NaOH solution (S.G = 1.478) is reacted with 275 liters of gaseous Cl2 (at STP). The product is analyzed and it is determined that 618 g of NaOCl was formed. Determine: The limiting reactant. The percent excess of the excess reactant, if any. The conversion. The yield of NaOCl.
Bleach (sodium hypochlorite, NaOCl) is produced by the reaction of a sodium hydroxide solution with chlorine...
Bleach (sodium hypochlorite, NaOCl) is produced by the reaction of a sodium hydroxide solution with chlorine gas. Water and NaCl are also produced in the reaction. 1.75 liters of a 45% NaOH solution (S.G = 1.478) is reacted with 275 liters of gaseous Cl2 (at STP). The product is analyzed and it is determined that 618 g of NaOCl was formed. Determine: The limiting reactant. The percent excess of the excess reactant, if any. The conversion. The yield of NaOCl.
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