1 mL of a 5.0 nM enzyme solution is rapidly mixed into 9 mL of a...

1 mL of a 5.0 nM enzyme solution is rapidly mixed into 9 mL of a 0.50 µM substrate solution, and the rate of formation of product is found to be 0.490 µM/s.

a) What are the initial concentrations of enzyme and substrate in the 10 mL mixture?

b) Calculate the Michaelis constant of the complex (KM), knowing that the rate of formation of product saturates to 0.670 µM/s when the experiment is performed with a highly concentrated substrate solution instead of the 0.50 µM substrate solution

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Amanda K answered 1 month ago

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