In: Statistics and Probability
A researcher wishes to estimate, with 99% confidence, the population proportion of adults who are confident with their country's banking system. His estimate must be accurate within 4% of the population proportion.
(a) No preliminary estimate is available. Find the minimum sample size needed.
(b) Find the minimum sample size needed, using a prior study that found that 32% of the respondents said they are confident with their country's banking system.
(c) Compare the results from parts (a) and (b).
(a) What is the minimum sample size needed assuming that no prior information is available?
Solution:
a ) Given that,
= 0.5
1 - = 1 - 0.5 = 0.5
margin of error = E = 4% = 0.04
At 99% confidence level the z is ,
= 1 - 99% = 1 - 0.99 = 0.01
/ 2 = 0.01 / 2 = 0.005
Z/2 = Z0.005 = 2.576
Sample size = n = ((Z / 2) / E)2 * * (1 - )
= (2.576 / 0.04)2 * 0.5 * 0.5
=1036.84
= 1037
n = sample size = 1037
b ) Given that,
= 0.32
1 - = 1 - 0.32 = 0.68
margin of error = E = 4% = 0.04
At 99% confidence level the z is ,
= 1 - 99% = 1 - 0.99 = 0.01
/ 2 = 0.01 / 2 = 0.005
Z/2 = Z0.005 = 2.576
Sample size = n = ((Z / 2) / E)2 * * (1 - )
= (2.576 / 0.04)2 * 0.32 * 0.68
= 902.46
= 902
n = sample size = 902
c ) Parts a ) is more than sample size of parts b )