In: Accounting
Rotorua Products, Ltd., of New Zealand markets agricultural products for the burgeoning Asian consumer market. The company’s current assets, current liabilities, and sales over the last five years (Year 5 is the most recent year) are as follows:
Year 1 | Year 2 | Year 3 | Year 4 | Year 5 | |||||||||||
Sales | $ | 4,509,210 | $ | 4,902,100 | $ | 4,979,250 | $ | 5,457,960 | $ | 5,801,230 | |||||
Cash | $ | 92,620 | $ | 92,634 | $ | 94,024 | $ | 72,295 | $ | 72,696 | |||||
Accounts receivable, net | 400,363 | 425,222 | 449,526 | 498,920 | 563,527 | ||||||||||
Inventory | 817,045 | 880,436 | 816,845 | 890,656 | 906,316 | ||||||||||
Total current assets | $ | 1,310,028 | $ | 1,398,292 | $ | 1,360,395 | $ | 1,461,871 | $ | 1,542,539 | |||||
Current liabilities | $ | 309,109 | $ | 332,592 | $ | 341,029 | $ | 324,140 | $ | 396,160 | |||||
Required:
1. Express all of the asset, liability, and sales data in trend percentages. Use Year 1 as the base year. (Round your percentage answers to 1 decimal place (i.e., 0.1234 should be entered as 12.3).)Rotorua Products, Ltd., of New Zealand markets agricultural products for the burgeoning Asian consumer market. The company’s current assets, current liabilities, and sales over the last five years (Year 5 is the most recent year) are as follows:
Year 1 | Year 2 | Year 3 | Year 4 | Year 5 | |||||||||||
Sales | $ | 4,509,210 | $ | 4,902,100 | $ | 4,979,250 | $ | 5,457,960 | $ | 5,801,230 | |||||
Cash | $ | 92,620 | $ | 92,634 | $ | 94,024 | $ | 72,295 | $ | 72,696 | |||||
Accounts receivable, net | 400,363 | 425,222 | 449,526 | 498,920 | 563,527 | ||||||||||
Inventory | 817,045 | 880,436 | 816,845 | 890,656 | 906,316 | ||||||||||
Total current assets | $ | 1,310,028 | $ | 1,398,292 | $ | 1,360,395 | $ | 1,461,871 | $ | 1,542,539 | |||||
Current liabilities | $ | 309,109 | $ | 332,592 | $ | 341,029 | $ | 324,140 | $ | 396,160 | |||||
Required:
1. Express all of the asset, liability, and sales data in trend percentages. Use Year 1 as the base year. (Round your percentage answers to 1 decimal place (i.e., 0.1234 should be entered as 12.3).)