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Twochargesof−5×10−9 Cand−2×10−9 C are separated by a distance of 38 cm. Find the equilibrium position for...

Twochargesof−5×10−9 Cand−2×10−9 C are separated by a distance of 38 cm. Find the equilibrium position for a third charge of +1.3 × 10−8 C by identifying its distance from the first charge q1. Answer in units of cm.

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The position of equilibrium from charge q1=23.28 cm

genius_generous answered 2 years ago
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